x^(1/2)+3x^(-1/2)=10x^(-3/2)

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Solution for x^(1/2)+3x^(-1/2)=10x^(-3/2) equation:


D( x )

x < 0

x = 0

x < 0

x = 0

x = 0

x in (0:+oo)

x^(1/2)+3*x^(-1/2) = 10*x^(-3/2) // - 10*x^(-3/2)

x^(1/2)+3*x^(-1/2)-(10*x^(-3/2)) = 0

x^(1/2)+3*x^(-1/2)-10*x^(-3/2) = 0

x^(1/2)+3*x^(-1/2)-10*x^(-3/2) = 0

x^(-1/2)*(x-10*x^-1+3) = 0

1*x^1-10*x^-1+3*x^0 = 0

(1*x^2+3*x^1-10*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+3*x^1-10*x^0) = 0

x^1

x^2+3*x-10 = 0

x^2+3*x-10 = 0

DELTA = 3^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-3)/(1*2) or x = (-49^(1/2)-3)/(1*2)

x = 2 or x = -5

x in { -5, 2}

1/(x^(1/2)) = 0

1*x^(-1/2) = 0 // : 1

x^(-1/2) = 0

x naleu017Cy do O

x in { -5}

x = 2

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